Search a number
-
+
114063245113 is a prime number
BaseRepresentation
bin110101000111010110…
…0101111111100111001
3101220102021010012210211
41222032230233330321
53332100142320423
6124222215111121
711145410405056
oct1521654577471
9356367105724
10114063245113
1144412801324
121a1336724a1
13a9aa26365c
145740abc02d
152e78bb210d
hex1a8eb2ff39

114063245113 has 2 divisors, whose sum is σ = 114063245114. Its totient is φ = 114063245112.

The previous prime is 114063245099. The next prime is 114063245123. The reversal of 114063245113 is 311542360411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113728794169 + 334450944 = 337237^2 + 18288^2 .

It is an emirp because it is prime and its reverse (311542360411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114063245113 - 25 = 114063245081 is a prime.

It is not a weakly prime, because it can be changed into another prime (114063245123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57031622556 + 57031622557.

It is an arithmetic number, because the mean of its divisors is an integer number (57031622557).

Almost surely, 2114063245113 is an apocalyptic number.

It is an amenable number.

114063245113 is a deficient number, since it is larger than the sum of its proper divisors (1).

114063245113 is an equidigital number, since it uses as much as digits as its factorization.

114063245113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

The spelling of 114063245113 in words is "one hundred fourteen billion, sixty-three million, two hundred forty-five thousand, one hundred thirteen".