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1140762433 is a prime number
BaseRepresentation
bin100001111111110…
…1010011101000001
32221111112201212111
41003333222131001
54314013344213
6305110255321
740161214666
oct10377523501
92844481774
101140762433
11535a26778
1227a057541
13152453575
14ab70da6d
156a238a3d
hex43fea741

1140762433 has 2 divisors, whose sum is σ = 1140762434. Its totient is φ = 1140762432.

The previous prime is 1140762419. The next prime is 1140762439. The reversal of 1140762433 is 3342670411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1092765249 + 47997184 = 33057^2 + 6928^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140762433 - 25 = 1140762401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140762395 and 1140762404.

It is not a weakly prime, because it can be changed into another prime (1140762439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570381216 + 570381217.

It is an arithmetic number, because the mean of its divisors is an integer number (570381217).

Almost surely, 21140762433 is an apocalyptic number.

It is an amenable number.

1140762433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140762433 is an equidigital number, since it uses as much as digits as its factorization.

1140762433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The square root of 1140762433 is about 33775.1748033967. The cubic root of 1140762433 is about 1044.8767611816.

The spelling of 1140762433 in words is "one billion, one hundred forty million, seven hundred sixty-two thousand, four hundred thirty-three".