Base | Representation |
---|---|
bin | 110101000111111101… |
… | …1000000011110101111 |
3 | 101220110200201111000012 |
4 | 1222033323000132233 |
5 | 3332120420310142 |
6 | 124224230523435 |
7 | 11146046650265 |
oct | 1521773003657 |
9 | 356420644005 |
10 | 114083760047 |
11 | 44423343514 |
12 | 1a13a50657b |
13 | a9b159727a |
14 | 57436dc435 |
15 | 2e7a8b5882 |
hex | 1a8fec07af |
114083760047 has 2 divisors, whose sum is σ = 114083760048. Its totient is φ = 114083760046.
The previous prime is 114083760019. The next prime is 114083760059. The reversal of 114083760047 is 740067380411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114083760047 - 214 = 114083743663 is a prime.
It is a super-2 number, since 2×1140837600472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114083759986 and 114083760013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114083760067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57041880023 + 57041880024.
It is an arithmetic number, because the mean of its divisors is an integer number (57041880024).
Almost surely, 2114083760047 is an apocalyptic number.
114083760047 is a deficient number, since it is larger than the sum of its proper divisors (1).
114083760047 is an equidigital number, since it uses as much as digits as its factorization.
114083760047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112896, while the sum is 41.
The spelling of 114083760047 in words is "one hundred fourteen billion, eighty-three million, seven hundred sixty thousand, forty-seven".
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