1140899113 has 2 divisors, whose sum is σ = 1140899114. Its totient is φ = 1140899112.

The previous prime is 1140899083. The next prime is 1140899117. The reversal of 1140899113 is 3119980411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 814988304 + 325910809 = 28548^2 + 18053^2 .

It is an emirp because it is prime and its reverse (3119980411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1140899113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140899117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570449556 + 570449557.

It is an arithmetic number, because the mean of its divisors is an integer number (570449557).

Almost surely, 2^1140899113 is an apocalyptic number.

It is an amenable number.

1140899113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140899113 is an equidigital number, since it uses as much as digits as its factorization.

1140899113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 37.

The square root of 1140899113 is about 33777.1981224020. The cubic root of 1140899113 is about 1044.9184900138.

The spelling of 1140899113 in words is "one billion, one hundred forty million, eight hundred ninety-nine thousand, one hundred thirteen".