Base | Representation |
---|---|
bin | 1101100110100… |
… | …00110010111001 |
3 | 21221200221202000 |
4 | 12303100302321 |
5 | 213202221213 |
6 | 15153331213 |
7 | 2553563145 |
oct | 663206271 |
9 | 257627660 |
10 | 114101433 |
11 | 59453106 |
12 | 32266b09 |
13 | 1a840154 |
14 | 11222225 |
15 | a03cc73 |
hex | 6cd0cb9 |
114101433 has 16 divisors (see below), whose sum is σ = 178983360. Its totient is φ = 71592768.
The previous prime is 114101423. The next prime is 114101437. The reversal of 114101433 is 334101411.
It is not a de Polignac number, because 114101433 - 28 = 114101177 is a prime.
It is a plaindrome in base 14.
It is not an unprimeable number, because it can be changed into a prime (114101437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 123835 + ... + 124752.
It is an arithmetic number, because the mean of its divisors is an integer number (11186460).
Almost surely, 2114101433 is an apocalyptic number.
It is an amenable number.
114101433 is a deficient number, since it is larger than the sum of its proper divisors (64881927).
114101433 is a wasteful number, since it uses less digits than its factorization.
114101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248613 (or 248607 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
The square root of 114101433 is about 10681.8272313308. The cubic root of 114101433 is about 485.0245256312.
Adding to 114101433 its reverse (334101411), we get a palindrome (448202844).
The spelling of 114101433 in words is "one hundred fourteen million, one hundred one thousand, four hundred thirty-three".
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