Base | Representation |
---|---|
bin | 1010011000001010010011… |
… | …1110100100000000001001 |
3 | 1111101210201112012122022212 |
4 | 2212002210332210000021 |
5 | 2443421042424030433 |
6 | 40133435102354505 |
7 | 2255234263156043 |
oct | 246024476440011 |
9 | 44353645178285 |
10 | 11410201001993 |
11 | 36aa048003072 |
12 | 134345928ba35 |
13 | 649c92297c41 |
14 | 2b6384460a93 |
15 | 14bc13916d48 |
hex | a60a4fa4009 |
11410201001993 has 2 divisors, whose sum is σ = 11410201001994. Its totient is φ = 11410201001992.
The previous prime is 11410201001963. The next prime is 11410201002041. The reversal of 11410201001993 is 39910010201411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8417965285129 + 2992235716864 = 2901373^2 + 1729808^2 .
It is a cyclic number.
It is not a de Polignac number, because 11410201001993 - 228 = 11409932566537 is a prime.
It is a super-2 number, since 2×114102010019932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11410201001963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705100500996 + 5705100500997.
It is an arithmetic number, because the mean of its divisors is an integer number (5705100500997).
Almost surely, 211410201001993 is an apocalyptic number.
It is an amenable number.
11410201001993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410201001993 is an equidigital number, since it uses as much as digits as its factorization.
11410201001993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
The spelling of 11410201001993 in words is "eleven trillion, four hundred ten billion, two hundred one million, one thousand, nine hundred ninety-three".
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