Base | Representation |
---|---|
bin | 1010011000001010010011… |
… | …1110100100000000111001 |
3 | 1111101210201112012122101122 |
4 | 2212002210332210000321 |
5 | 2443421042424031131 |
6 | 40133435102355025 |
7 | 2255234263156142 |
oct | 246024476440071 |
9 | 44353645178348 |
10 | 11410201002041 |
11 | 36aa048003106 |
12 | 134345928ba75 |
13 | 649c92297c7a |
14 | 2b6384460ac9 |
15 | 14bc13916d7b |
hex | a60a4fa4039 |
11410201002041 has 2 divisors, whose sum is σ = 11410201002042. Its totient is φ = 11410201002040.
The previous prime is 11410201001993. The next prime is 11410201002061. The reversal of 11410201002041 is 14020010201411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7141700380816 + 4268500621225 = 2672396^2 + 2066035^2 .
It is a cyclic number.
It is not a de Polignac number, because 11410201002041 - 214 = 11410200985657 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11410201002061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705100501020 + 5705100501021.
It is an arithmetic number, because the mean of its divisors is an integer number (5705100501021).
Almost surely, 211410201002041 is an apocalyptic number.
It is an amenable number.
11410201002041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410201002041 is an equidigital number, since it uses as much as digits as its factorization.
11410201002041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11410201002041 its reverse (14020010201411), we get a palindrome (25430211203452).
The spelling of 11410201002041 in words is "eleven trillion, four hundred ten billion, two hundred one million, two thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •