Base | Representation |
---|---|
bin | 1010011000001010011110… |
… | …0100000111111100110001 |
3 | 1111101210211112212122022022 |
4 | 2212002213210013330301 |
5 | 2443421140031343433 |
6 | 40133443252521225 |
7 | 2255235331110422 |
oct | 246024744077461 |
9 | 44353745778268 |
10 | 11410244402993 |
11 | 36aa06a556967 |
12 | 134346b920215 |
13 | 649c9b2827c7 |
14 | 2b638a11b649 |
15 | 14bc1763b698 |
hex | a60a7907f31 |
11410244402993 has 2 divisors, whose sum is σ = 11410244402994. Its totient is φ = 11410244402992.
The previous prime is 11410244402987. The next prime is 11410244403001. The reversal of 11410244402993 is 39920444201411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9877518693904 + 1532725709089 = 3142852^2 + 1238033^2 .
It is a cyclic number.
It is not a de Polignac number, because 11410244402993 - 212 = 11410244398897 is a prime.
It is not a weakly prime, because it can be changed into another prime (11410244102993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705122201496 + 5705122201497.
It is an arithmetic number, because the mean of its divisors is an integer number (5705122201497).
Almost surely, 211410244402993 is an apocalyptic number.
It is an amenable number.
11410244402993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410244402993 is an equidigital number, since it uses as much as digits as its factorization.
11410244402993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 44.
The spelling of 11410244402993 in words is "eleven trillion, four hundred ten billion, two hundred forty-four million, four hundred two thousand, nine hundred ninety-three".
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