Base | Representation |
---|---|
bin | 1010011000001010011110… |
… | …0100000111111100111001 |
3 | 1111101210211112212122022121 |
4 | 2212002213210013330321 |
5 | 2443421140031344001 |
6 | 40133443252521241 |
7 | 2255235331110433 |
oct | 246024744077471 |
9 | 44353745778277 |
10 | 11410244403001 |
11 | 36aa06a556974 |
12 | 134346b920221 |
13 | 649c9b282802 |
14 | 2b638a11b653 |
15 | 14bc1763b6a1 |
hex | a60a7907f39 |
11410244403001 has 2 divisors, whose sum is σ = 11410244403002. Its totient is φ = 11410244403000.
The previous prime is 11410244402993. The next prime is 11410244403067. The reversal of 11410244403001 is 10030444201411.
11410244403001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11110882223401 + 299362179600 = 3333299^2 + 547140^2 .
It is a cyclic number.
It is not a de Polignac number, because 11410244403001 - 23 = 11410244402993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11410244400001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705122201500 + 5705122201501.
It is an arithmetic number, because the mean of its divisors is an integer number (5705122201501).
Almost surely, 211410244403001 is an apocalyptic number.
It is an amenable number.
11410244403001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410244403001 is an equidigital number, since it uses as much as digits as its factorization.
11410244403001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11410244403001 its reverse (10030444201411), we get a palindrome (21440688604412).
The spelling of 11410244403001 in words is "eleven trillion, four hundred ten billion, two hundred forty-four million, four hundred three thousand, one".
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