Base | Representation |
---|---|
bin | 1010011000001011000100… |
… | …0110100011101011100111 |
3 | 1111101211020200222120102221 |
4 | 2212002301012203223213 |
5 | 2443422002013040143 |
6 | 40133511210413211 |
7 | 2255242313216254 |
oct | 246026106435347 |
9 | 44354220876387 |
10 | 11410404424423 |
11 | 36aa141913384 |
12 | 13434b5431207 |
13 | 649cc547cc44 |
14 | 2b63a349442b |
15 | 14bc266ea2ed |
hex | a60b11a3ae7 |
11410404424423 has 4 divisors (see below), whose sum is σ = 11410970914528. Its totient is φ = 11409837934320.
The previous prime is 11410404424409. The next prime is 11410404424459. The reversal of 11410404424423 is 32442440401411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11410404424423 - 237 = 11272965470951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11410404464423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283214838 + ... + 283255123.
It is an arithmetic number, because the mean of its divisors is an integer number (2852742728632).
Almost surely, 211410404424423 is an apocalyptic number.
11410404424423 is a deficient number, since it is larger than the sum of its proper divisors (566490105).
11410404424423 is an equidigital number, since it uses as much as digits as its factorization.
11410404424423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566490104.
The product of its (nonzero) digits is 49152, while the sum is 34.
Adding to 11410404424423 its reverse (32442440401411), we get a palindrome (43852844825834).
The spelling of 11410404424423 in words is "eleven trillion, four hundred ten billion, four hundred four million, four hundred twenty-four thousand, four hundred twenty-three".
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