Search a number
-
+
11410505223317 is a prime number
BaseRepresentation
bin1010011000001011011100…
…0111000100110010010101
31111101211111201122200112022
42212002313013010302111
52443422203314121232
640133525211102525
72255244646046504
oct246026707046225
944354451580468
1011410505223317
1136aa193800052
121343523141a45
1364a010313265
142b63b2a1283b
1514bc304ab812
hexa60b71c4c95

11410505223317 has 2 divisors, whose sum is σ = 11410505223318. Its totient is φ = 11410505223316.

The previous prime is 11410505223289. The next prime is 11410505223371. The reversal of 11410505223317 is 71332250501411.

Together with next prime (11410505223371) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11171163144241 + 239342079076 = 3342329^2 + 489226^2 .

It is a cyclic number.

It is not a de Polignac number, because 11410505223317 - 216 = 11410505157781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11410505223017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705252611658 + 5705252611659.

It is an arithmetic number, because the mean of its divisors is an integer number (5705252611659).

Almost surely, 211410505223317 is an apocalyptic number.

It is an amenable number.

11410505223317 is a deficient number, since it is larger than the sum of its proper divisors (1).

11410505223317 is an equidigital number, since it uses as much as digits as its factorization.

11410505223317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 35.

Adding to 11410505223317 its reverse (71332250501411), we get a palindrome (82742755724728).

The spelling of 11410505223317 in words is "eleven trillion, four hundred ten billion, five hundred five million, two hundred twenty-three thousand, three hundred seventeen".