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114107113 is a prime number
BaseRepresentation
bin1101100110100…
…10001011101001
321221201020112101
412303102023221
5213202411423
615153413401
72553615541
oct663221351
9257636471
10114107113
11594573aa
123226a261
131a842903
1411224321
15a03e7ad
hex6cd22e9

114107113 has 2 divisors, whose sum is σ = 114107114. Its totient is φ = 114107112.

The previous prime is 114107107. The next prime is 114107131. The reversal of 114107113 is 311701411.

It is a happy number.

Together with next prime (114107131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87759424 + 26347689 = 9368^2 + 5133^2 .

It is a cyclic number.

It is not a de Polignac number, because 114107113 - 213 = 114098921 is a prime.

It is not a weakly prime, because it can be changed into another prime (114107143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57053556 + 57053557.

It is an arithmetic number, because the mean of its divisors is an integer number (57053557).

Almost surely, 2114107113 is an apocalyptic number.

It is an amenable number.

114107113 is a deficient number, since it is larger than the sum of its proper divisors (1).

114107113 is an equidigital number, since it uses as much as digits as its factorization.

114107113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

The square root of 114107113 is about 10682.0931001373. The cubic root of 114107113 is about 485.0325737147.

Adding to 114107113 its reverse (311701411), we get a palindrome (425808524).

The spelling of 114107113 in words is "one hundred fourteen million, one hundred seven thousand, one hundred thirteen".