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114111300214 = 2193002928953
BaseRepresentation
bin110101001000110010…
…0000100001001110110
3101220112121112200000101
41222101210010021312
53332144443101324
6124231053104314
711146533022312
oct1522144041166
9356477480011
10114111300214
114443794388a
121a14778809a
13a9b71ba722
14574722ab42
152e7d005944
hex1a91904276

114111300214 has 8 divisors (see below), whose sum is σ = 180175737240. Its totient is φ = 54052721136.

The previous prime is 114111300211. The next prime is 114111300227. The reversal of 114111300214 is 412003111411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a junction number, because it is equal to n+sod(n) for n = 114111300191 and 114111300200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114111300211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1501464439 + ... + 1501464514.

It is an arithmetic number, because the mean of its divisors is an integer number (22521967155).

Almost surely, 2114111300214 is an apocalyptic number.

114111300214 is a deficient number, since it is larger than the sum of its proper divisors (66064437026).

114111300214 is a wasteful number, since it uses less digits than its factorization.

114111300214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3002928974.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 114111300214 its reverse (412003111411), we get a palindrome (526114411625).

The spelling of 114111300214 in words is "one hundred fourteen billion, one hundred eleven million, three hundred thousand, two hundred fourteen".

Divisors: 1 2 19 38 3002928953 6005857906 57055650107 114111300214