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11411210401 is a prime number
BaseRepresentation
bin10101010000010100…
…10100000010100001
31002110021012112212021
422220022110002201
5141332232213101
65124153501441
7552531454663
oct125012240241
932407175767
1011411210401
1149263702a8
122265711881
1310cb192706
147a3752533
1546bc195a1
hex2a82940a1

11411210401 has 2 divisors, whose sum is σ = 11411210402. Its totient is φ = 11411210400.

The previous prime is 11411210357. The next prime is 11411210411. The reversal of 11411210401 is 10401211411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6103359376 + 5307851025 = 78124^2 + 72855^2 .

It is an emirp because it is prime and its reverse (10401211411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11411210401 - 27 = 11411210273 is a prime.

It is a super-3 number, since 3×114112104013 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11411210411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705605200 + 5705605201.

It is an arithmetic number, because the mean of its divisors is an integer number (5705605201).

Almost surely, 211411210401 is an apocalyptic number.

It is an amenable number.

11411210401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411210401 is an equidigital number, since it uses as much as digits as its factorization.

11411210401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 11411210401 its reverse (10401211411), we get a palindrome (21812421812).

The spelling of 11411210401 in words is "eleven billion, four hundred eleven million, two hundred ten thousand, four hundred one".