Base | Representation |
---|---|
bin | 1010011000001110000101… |
… | …1000001011111100000010 |
3 | 1111101220100011000011101102 |
4 | 2212003201120023330002 |
5 | 2443430131333232010 |
6 | 40134123422134402 |
7 | 2255301346411445 |
oct | 246034130137402 |
9 | 44356304004342 |
10 | 11411214352130 |
11 | 36aa51801501a |
12 | 13436a0721402 |
13 | 64a0c41ca7c8 |
14 | 2b643cc8565c |
15 | 14bc72883ba5 |
hex | a60e160bf02 |
11411214352130 has 8 divisors (see below), whose sum is σ = 20540185833852. Its totient is φ = 4564485740848.
The previous prime is 11411214352127. The next prime is 11411214352157. The reversal of 11411214352130 is 3125341211411.
It can be written as a sum of positive squares in 2 ways, for example, as 11296650380401 + 114563971729 = 3361049^2 + 338473^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 11411214352093 and 11411214352102.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570560717597 + ... + 570560717616.
Almost surely, 211411214352130 is an apocalyptic number.
11411214352130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11411214352130 is a deficient number, since it is larger than the sum of its proper divisors (9128971481722).
11411214352130 is a wasteful number, since it uses less digits than its factorization.
11411214352130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1141121435220.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 11411214352130 its reverse (3125341211411), we get a palindrome (14536555563541).
The spelling of 11411214352130 in words is "eleven trillion, four hundred eleven billion, two hundred fourteen million, three hundred fifty-two thousand, one hundred thirty".
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