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1141124401213 = 4724279242579
BaseRepresentation
bin10000100110110000010…
…100001000100000111101
311001002102220212210201121
4100212300110020200331
5122144010321314323
62232120400110541
7145305061240666
oct20466024104075
94032386783647
101141124401213
113aaa47a80335
121651a8305451
13837b8aa2ca4
143d33312636d
151ea3b03da5d
hex109b050883d

1141124401213 has 4 divisors (see below), whose sum is σ = 1165403643840. Its totient is φ = 1116845158588.

The previous prime is 1141124401201. The next prime is 1141124401253. The reversal of 1141124401213 is 3121044211411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1141124401213 - 29 = 1141124400701 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141124401253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12139621243 + ... + 12139621336.

It is an arithmetic number, because the mean of its divisors is an integer number (291350910960).

Almost surely, 21141124401213 is an apocalyptic number.

It is an amenable number.

1141124401213 is a deficient number, since it is larger than the sum of its proper divisors (24279242627).

1141124401213 is an equidigital number, since it uses as much as digits as its factorization.

1141124401213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24279242626.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1141124401213 its reverse (3121044211411), we get a palindrome (4262168612624).

The spelling of 1141124401213 in words is "one trillion, one hundred forty-one billion, one hundred twenty-four million, four hundred one thousand, two hundred thirteen".

Divisors: 1 47 24279242579 1141124401213