Base | Representation |
---|---|
bin | 10000100110110000110… |
… | …001101010001010011101 |
3 | 11001002110110110001000021 |
4 | 100212300301222022131 |
5 | 122144014312004323 |
6 | 2232121234032141 |
7 | 145305214105411 |
oct | 20466061521235 |
9 | 4032413401007 |
10 | 1141132141213 |
11 | 3aaa51387529 |
12 | 1651aaa18651 |
13 | 837ba582c7c |
14 | 3d33417cd41 |
15 | 1ea3ba6c05d |
hex | 109b0c6a29d |
1141132141213 has 2 divisors, whose sum is σ = 1141132141214. Its totient is φ = 1141132141212.
The previous prime is 1141132141189. The next prime is 1141132141301. The reversal of 1141132141213 is 3121412311411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 604316554884 + 536815586329 = 777378^2 + 732677^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141132141213 - 213 = 1141132133021 is a prime.
It is a super-2 number, since 2×11411321412132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141132141013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570566070606 + 570566070607.
It is an arithmetic number, because the mean of its divisors is an integer number (570566070607).
Almost surely, 21141132141213 is an apocalyptic number.
It is an amenable number.
1141132141213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141132141213 is an equidigital number, since it uses as much as digits as its factorization.
1141132141213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 25.
Adding to 1141132141213 its reverse (3121412311411), we get a palindrome (4262544452624).
The spelling of 1141132141213 in words is "one trillion, one hundred forty-one billion, one hundred thirty-two million, one hundred forty-one thousand, two hundred thirteen".
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