Base | Representation |
---|---|
bin | 1010011000001110100110… |
… | …0111010000100101111011 |
3 | 1111101220200202222212120001 |
4 | 2212003221213100211323 |
5 | 2443430422221133313 |
6 | 40134145235413431 |
7 | 2255304645004414 |
oct | 246035147204573 |
9 | 44356622885501 |
10 | 11411352521083 |
11 | 36aa589006439 |
12 | 134371aa54277 |
13 | 64a116a16598 |
14 | 2b645337080b |
15 | 14bc7ea77add |
hex | a60e99d097b |
11411352521083 has 2 divisors, whose sum is σ = 11411352521084. Its totient is φ = 11411352521082.
The previous prime is 11411352521081. The next prime is 11411352521113. The reversal of 11411352521083 is 38012525311411.
11411352521083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11411352521083 - 21 = 11411352521081 is a prime.
Together with 11411352521081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11411352521081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705676260541 + 5705676260542.
It is an arithmetic number, because the mean of its divisors is an integer number (5705676260542).
Almost surely, 211411352521083 is an apocalyptic number.
11411352521083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411352521083 is an equidigital number, since it uses as much as digits as its factorization.
11411352521083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 37.
Adding to 11411352521083 its reverse (38012525311411), we get a palindrome (49423877832494).
The spelling of 11411352521083 in words is "eleven trillion, four hundred eleven billion, three hundred fifty-two million, five hundred twenty-one thousand, eighty-three".
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