114114113 has 4 divisors (see below), whose sum is σ = 114222528. Its totient is φ = 114005700.

The previous prime is 114114097. The next prime is 114114151. The reversal of 114114113 is 311411411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311411411 = 53 ⋅5875687.

It is a cyclic number.

It is not a de Polignac number, because 114114113 - 2⁴ = 114114097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114114091 and 114114100.

It is not an unprimeable number, because it can be changed into a prime (114113113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52613 + ... + 54738.

It is an arithmetic number, because the mean of its divisors is an integer number (28555632).

Almost surely, 2^114114113 is an apocalyptic number.

It is an amenable number.

114114113 is a deficient number, since it is larger than the sum of its proper divisors (108415).

114114113 is a wasteful number, since it uses less digits than its factorization.

114114113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108414.

The product of its digits is 48, while the sum is 17.

The square root of 114114113 is about 10682.4207462541. The cubic root of 114114113 is about 485.0424917602.

Adding to 114114113 its reverse (311411411), we get a palindrome (425525524).

The spelling of 114114113 in words is "one hundred fourteen million, one hundred fourteen thousand, one hundred thirteen".