Base | Representation |
---|---|
bin | 11001111100100101010000… |
… | …001011101100010111011010 |
3 | 112222001020000221210211012022 |
4 | 121330211100023230113122 |
5 | 104424122122310030020 |
6 | 1042411222231014442 |
7 | 33015326340014504 |
oct | 3174452013542732 |
9 | 488036027724168 |
10 | 114114331330010 |
11 | 333a6686099250 |
12 | 1097015680a422 |
13 | 4b89c20a3574b |
14 | 202723d7c4d74 |
15 | d2d597b87625 |
hex | 67c9502ec5da |
114114331330010 has 64 divisors (see below), whose sum is σ = 227986960314240. Its totient is φ = 40778154362880.
The previous prime is 114114331330009. The next prime is 114114331330031. The reversal of 114114331330010 is 10033133411411.
It is a super-2 number, since 2×1141143313300102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34159487 + ... + 37351026.
It is an arithmetic number, because the mean of its divisors is an integer number (3562296254910).
Almost surely, 2114114331330010 is an apocalyptic number.
114114331330010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114114331330010 is a deficient number, since it is larger than the sum of its proper divisors (113872628984230).
114114331330010 is a wasteful number, since it uses less digits than its factorization.
114114331330010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71510783.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 114114331330010 its reverse (10033133411411), we get a palindrome (124147464741421).
The spelling of 114114331330010 in words is "one hundred fourteen trillion, one hundred fourteen billion, three hundred thirty-one million, three hundred thirty thousand, ten".
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