Base | Representation |
---|---|
bin | 10101010000011010… |
… | …10100110011111001 |
3 | 1002110022200122222102 |
4 | 22220031110303321 |
5 | 141332432444433 |
6 | 5124222433145 |
7 | 552541254002 |
oct | 125015246371 |
9 | 32408618872 |
10 | 11411999993 |
11 | 492685a559 |
12 | 2265a327b5 |
13 | 10cb3aac24 |
14 | 7a38ba1a9 |
15 | 46bd234e8 |
hex | 2a8354cf9 |
11411999993 has 2 divisors, whose sum is σ = 11411999994. Its totient is φ = 11411999992.
The previous prime is 11411999959. The next prime is 11412000031. The reversal of 11411999993 is 39999911411.
11411999993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8366395024 + 3045604969 = 91468^2 + 55187^2 .
It is a cyclic number.
It is not a de Polignac number, because 11411999993 - 224 = 11395222777 is a prime.
It is not a weakly prime, because it can be changed into another prime (11411998993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705999996 + 5705999997.
It is an arithmetic number, because the mean of its divisors is an integer number (5705999997).
Almost surely, 211411999993 is an apocalyptic number.
It is an amenable number.
11411999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411999993 is an equidigital number, since it uses as much as digits as its factorization.
11411999993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 708588, while the sum is 56.
The spelling of 11411999993 in words is "eleven billion, four hundred eleven million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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