1141213433 has 4 divisors (see below), whose sum is σ = 1141335888. Its totient is φ = 1141090980.

The previous prime is 1141213429. The next prime is 1141213441. The reversal of 1141213433 is 3343121411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3343121411 = 7 ⋅477588773.

It is a cyclic number.

It is not a de Polignac number, because 1141213433 - 2² = 1141213429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1141213399 and 1141213408.

It is not an unprimeable number, because it can be changed into a prime (1141219433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45983 + ... + 66308.

It is an arithmetic number, because the mean of its divisors is an integer number (285333972).

Almost surely, 2^1141213433 is an apocalyptic number.

It is an amenable number.

1141213433 is a deficient number, since it is larger than the sum of its proper divisors (122455).

1141213433 is a wasteful number, since it uses less digits than its factorization.

1141213433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122454.

The product of its digits is 864, while the sum is 23.

The square root of 1141213433 is about 33781.8506449839. The cubic root of 1141213433 is about 1045.0144402513.

Adding to 1141213433 its reverse (3343121411), we get a palindrome (4484334844).

The spelling of 1141213433 in words is "one billion, one hundred forty-one million, two hundred thirteen thousand, four hundred thirty-three".