Base | Representation |
---|---|
bin | 1010011000010001110011… |
… | …1111100100010101010011 |
3 | 1111101222220212000112102111 |
4 | 2212010130333210111103 |
5 | 2443434203410001121 |
6 | 40134410551330151 |
7 | 2255335212660151 |
oct | 246043477442523 |
9 | 44358825015374 |
10 | 11412214531411 |
11 | 36aa990650571 |
12 | 134391b680957 |
13 | 64a22349b475 |
14 | 2b64d5a3c3d1 |
15 | 14bcd059d2e1 |
hex | a611cfe4553 |
11412214531411 has 2 divisors, whose sum is σ = 11412214531412. Its totient is φ = 11412214531410.
The previous prime is 11412214531379. The next prime is 11412214531433. The reversal of 11412214531411 is 11413541221411.
It is a happy number.
11412214531411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11412214531411 - 25 = 11412214531379 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412214531441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706107265705 + 5706107265706.
It is an arithmetic number, because the mean of its divisors is an integer number (5706107265706).
Almost surely, 211412214531411 is an apocalyptic number.
11412214531411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412214531411 is an equidigital number, since it uses as much as digits as its factorization.
11412214531411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3840, while the sum is 31.
Adding to 11412214531411 its reverse (11413541221411), we get a palindrome (22825755752822).
The spelling of 11412214531411 in words is "eleven trillion, four hundred twelve billion, two hundred fourteen million, five hundred thirty-one thousand, four hundred eleven".
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