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114123000037 is a prime number
BaseRepresentation
bin110101001001001000…
…0101100100011100101
3101220120102120002011011
41222102100230203211
53332210442000122
6124232151542221
711150034331504
oct1522220544345
9356512502134
10114123000037
1144443505062
121a14b68a971
13a9b9755bb7
1457489d483b
152e7e067377
hex1a9242c8e5

114123000037 has 2 divisors, whose sum is σ = 114123000038. Its totient is φ = 114123000036.

The previous prime is 114122999933. The next prime is 114123000049. The reversal of 114123000037 is 730000321411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76706287681 + 37416712356 = 276959^2 + 193434^2 .

It is an emirp because it is prime and its reverse (730000321411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114123000037 - 27 = 114122999909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114122999981 and 114123000017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114123000097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061500018 + 57061500019.

It is an arithmetic number, because the mean of its divisors is an integer number (57061500019).

Almost surely, 2114123000037 is an apocalyptic number.

It is an amenable number.

114123000037 is a deficient number, since it is larger than the sum of its proper divisors (1).

114123000037 is an equidigital number, since it uses as much as digits as its factorization.

114123000037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 22.

Adding to 114123000037 its reverse (730000321411), we get a palindrome (844123321448).

The spelling of 114123000037 in words is "one hundred fourteen billion, one hundred twenty-three million, thirty-seven", and thus it is an aban number.