Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101110111100101 |
3 | 11001002201111212200002122 |
4 | 100212312303231313211 |
5 | 122144221214001343 |
6 | 2232135251115325 |
7 | 145310553240242 |
oct | 20466663556745 |
9 | 4032644780078 |
10 | 1141233343973 |
11 | 3aaaa351a678 |
12 | 1652188a2b45 |
13 | 83805528068 |
14 | 3d3437a45c9 |
15 | 1ea458ad068 |
hex | 109b6cedde5 |
1141233343973 has 2 divisors, whose sum is σ = 1141233343974. Its totient is φ = 1141233343972.
The previous prime is 1141233343937. The next prime is 1141233343981. The reversal of 1141233343973 is 3793433321411.
Together with previous prime (1141233343937) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 888507956449 + 252725387524 = 942607^2 + 502718^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141233343973 - 220 = 1141232295397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141233343993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616671986 + 570616671987.
It is an arithmetic number, because the mean of its divisors is an integer number (570616671987).
Almost surely, 21141233343973 is an apocalyptic number.
It is an amenable number.
1141233343973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141233343973 is an equidigital number, since it uses as much as digits as its factorization.
1141233343973 is an evil number, because the sum of its binary digits is even.
The product of its digits is 489888, while the sum is 44.
The spelling of 1141233343973 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-three thousand, nine hundred seventy-three".
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