Base | Representation |
---|---|
bin | 110101001001001001… |
… | …0110001011100011111 |
3 | 101220120110120201210221 |
4 | 1222102102301130133 |
5 | 3332211111404401 |
6 | 124232211342211 |
7 | 11150042056435 |
oct | 1522222613437 |
9 | 356513521727 |
10 | 114123544351 |
11 | 44443847003 |
12 | 1a14b8b1967 |
13 | a9b98b688b |
14 | 5748ad6d55 |
15 | 2e7e1237a1 |
hex | 1a924b171f |
114123544351 has 2 divisors, whose sum is σ = 114123544352. Its totient is φ = 114123544350.
The previous prime is 114123544343. The next prime is 114123544411. The reversal of 114123544351 is 153445321411.
It is a weak prime.
It is an emirp because it is prime and its reverse (153445321411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114123544351 - 23 = 114123544343 is a prime.
It is a super-2 number, since 2×1141235443512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114121544351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061772175 + 57061772176.
It is an arithmetic number, because the mean of its divisors is an integer number (57061772176).
Almost surely, 2114123544351 is an apocalyptic number.
114123544351 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123544351 is an equidigital number, since it uses as much as digits as its factorization.
114123544351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28800, while the sum is 34.
Adding to 114123544351 its reverse (153445321411), we get a palindrome (267568865762).
The spelling of 114123544351 in words is "one hundred fourteen billion, one hundred twenty-three million, five hundred forty-four thousand, three hundred fifty-one".
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