Base | Representation |
---|---|
bin | 110101001001001001… |
… | …0110001011110010111 |
3 | 101220120110120201222101 |
4 | 1222102102301132113 |
5 | 3332211111410341 |
6 | 124232211342531 |
7 | 11150042056666 |
oct | 1522222613627 |
9 | 356513521871 |
10 | 114123544471 |
11 | 44443847102 |
12 | 1a14b8b1a47 |
13 | a9b98b6951 |
14 | 5748ad6ddd |
15 | 2e7e123831 |
hex | 1a924b1797 |
114123544471 has 2 divisors, whose sum is σ = 114123544472. Its totient is φ = 114123544470.
The previous prime is 114123544411. The next prime is 114123544511. The reversal of 114123544471 is 174445321411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114123544471 - 27 = 114123544343 is a prime.
It is a super-3 number, since 3×1141235444713 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 114123544471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114123544411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061772235 + 57061772236.
It is an arithmetic number, because the mean of its divisors is an integer number (57061772236).
Almost surely, 2114123544471 is an apocalyptic number.
114123544471 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123544471 is an equidigital number, since it uses as much as digits as its factorization.
114123544471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 53760, while the sum is 37.
Adding to 114123544471 its reverse (174445321411), we get a palindrome (288568865882).
The spelling of 114123544471 in words is "one hundred fourteen billion, one hundred twenty-three million, five hundred forty-four thousand, four hundred seventy-one".
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