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11412422103 = 319697193133
BaseRepresentation
bin10101010000011101…
…11011110111010111
31002110100111010000010
422220032323313113
5141333040001403
65124235451303
7552544662435
oct125016736727
932410433003
1011412422103
114927018705
122265bb6b33
1310cb4c80b4
147a3989d55
1546bda8603
hex2a83bbdd7

11412422103 has 8 divisors (see below), whose sum is σ = 15217414128. Its totient is φ = 7607855744.

The previous prime is 11412422093. The next prime is 11412422137. The reversal of 11412422103 is 30122421411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11412422103 - 25 = 11412422071 is a prime.

It is a super-3 number, since 3×114124221033 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11412422103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11412422603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37476 + ... + 155657.

It is an arithmetic number, because the mean of its divisors is an integer number (1902176766).

Almost surely, 211412422103 is an apocalyptic number.

11412422103 is a deficient number, since it is larger than the sum of its proper divisors (3804992025).

11412422103 is a wasteful number, since it uses less digits than its factorization.

11412422103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212833.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 11412422103 its reverse (30122421411), we get a palindrome (41534843514).

The spelling of 11412422103 in words is "eleven billion, four hundred twelve million, four hundred twenty-two thousand, one hundred three".

Divisors: 1 3 19697 59091 193133 579399 3804140701 11412422103