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11412433303 is a prime number
BaseRepresentation
bin10101010000011101…
…11110100110010111
31002110100111200100221
422220032332212113
5141333040331203
65124240015211
7552545040205
oct125016764627
932410450327
1011412433303
114927026067
122266001507
1310cb50021b
147a3990075
1546bdababd
hex2a83be997

11412433303 has 2 divisors, whose sum is σ = 11412433304. Its totient is φ = 11412433302.

The previous prime is 11412433259. The next prime is 11412433327. The reversal of 11412433303 is 30333421411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11412433303 - 213 = 11412425111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11412433363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706216651 + 5706216652.

It is an arithmetic number, because the mean of its divisors is an integer number (5706216652).

Almost surely, 211412433303 is an apocalyptic number.

11412433303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412433303 is an equidigital number, since it uses as much as digits as its factorization.

11412433303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11412433303 its reverse (30333421411), we get a palindrome (41745854714).

The spelling of 11412433303 in words is "eleven billion, four hundred twelve million, four hundred thirty-three thousand, three hundred three".