Base | Representation |
---|---|
bin | 10000100110110111011… |
… | …101101111100110010001 |
3 | 11001002202021121101202120 |
4 | 100212313131233212101 |
5 | 122144232024023410 |
6 | 2232140323204453 |
7 | 145311046004202 |
oct | 20466735574621 |
9 | 4032667541676 |
10 | 1141244361105 |
11 | 3aaaa9764a42 |
12 | 165220516729 |
13 | 838078b4884 |
14 | 3d3450315a9 |
15 | 1ea46837570 |
hex | 109b776f991 |
1141244361105 has 16 divisors (see below), whose sum is σ = 1826592298944. Its totient is φ = 608463218880.
The previous prime is 1141244361083. The next prime is 1141244361137. The reversal of 1141244361105 is 5011634421411.
It is not a de Polignac number, because 1141244361105 - 29 = 1141244360593 is a prime.
It is a super-3 number, since 3×11412443611053 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12480451 + ... + 12571560.
It is an arithmetic number, because the mean of its divisors is an integer number (114162018684).
Almost surely, 21141244361105 is an apocalyptic number.
1141244361105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1141244361105 is a deficient number, since it is larger than the sum of its proper divisors (685347937839).
1141244361105 is a wasteful number, since it uses less digits than its factorization.
1141244361105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25055056.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 1141244361105 its reverse (5011634421411), we get a palindrome (6152878782516).
The spelling of 1141244361105 in words is "one trillion, one hundred forty-one billion, two hundred forty-four million, three hundred sixty-one thousand, one hundred five".
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