Base | Representation |
---|---|
bin | 11001111100101110101010… |
… | …111010010110001100100001 |
3 | 112222002012010200112102210201 |
4 | 121330232222322112030201 |
5 | 104424303330010202001 |
6 | 1042420013500425201 |
7 | 33016135045404424 |
oct | 3174565272261441 |
9 | 488065120472721 |
10 | 114124443444001 |
11 | 333aa9a5119151 |
12 | 109720b9248201 |
13 | 4b8ab72a18553 |
14 | 202791c7ad9bb |
15 | d2d98a7de501 |
hex | 67cbaae96321 |
114124443444001 has 2 divisors, whose sum is σ = 114124443444002. Its totient is φ = 114124443444000.
The previous prime is 114124443443987. The next prime is 114124443444041. The reversal of 114124443444001 is 100444344421411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89157482520976 + 24966960923025 = 9442324^2 + 4996695^2 .
It is a cyclic number.
It is not a de Polignac number, because 114124443444001 - 215 = 114124443411233 is a prime.
It is not a weakly prime, because it can be changed into another prime (114124443444041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57062221722000 + 57062221722001.
It is an arithmetic number, because the mean of its divisors is an integer number (57062221722001).
Almost surely, 2114124443444001 is an apocalyptic number.
It is an amenable number.
114124443444001 is a deficient number, since it is larger than the sum of its proper divisors (1).
114124443444001 is an equidigital number, since it uses as much as digits as its factorization.
114124443444001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 98304, while the sum is 37.
Adding to 114124443444001 its reverse (100444344421411), we get a palindrome (214568787865412).
The spelling of 114124443444001 in words is "one hundred fourteen trillion, one hundred twenty-four billion, four hundred forty-three million, four hundred forty-four thousand, one".
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