114125055015133 has 4 divisors (see below), whose sum is σ = 114125105943328. Its totient is φ = 114125004086940.

The previous prime is 114125055015131. The next prime is 114125055015173. The reversal of 114125055015133 is 331510550521411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114125055015133 - 2¹ = 114125055015131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114125055015092 and 114125055015101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114125055015131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21940191 + ... + 26638732.

It is an arithmetic number, because the mean of its divisors is an integer number (28531276485832).

Almost surely, 2^{114125055015133} is an apocalyptic number.

It is an amenable number.

114125055015133 is a deficient number, since it is larger than the sum of its proper divisors (50928195).

114125055015133 is an equidigital number, since it uses as much as digits as its factorization.

114125055015133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50928194.

The product of its (nonzero) digits is 45000, while the sum is 37.

The spelling of 114125055015133 in words is "one hundred fourteen trillion, one hundred twenty-five billion, fifty-five million, fifteen thousand, one hundred thirty-three".