Base | Representation |
---|---|
bin | 11001111100101111100101… |
… | …001000100101010100101111 |
3 | 112222002021122202120112220202 |
4 | 121330233211020211110233 |
5 | 104424312330041121021 |
6 | 1042420254433104115 |
7 | 33016201206223451 |
oct | 3174574510452457 |
9 | 488067582515822 |
10 | 114125420254511 |
11 | 33400356543366 |
12 | 109723303b803b |
13 | 4b8ac9a1c6633 |
14 | 20279b24022d1 |
15 | d2d9e643ea0b |
hex | 67cbe522552f |
114125420254511 has 2 divisors, whose sum is σ = 114125420254512. Its totient is φ = 114125420254510.
The previous prime is 114125420254409. The next prime is 114125420254553. The reversal of 114125420254511 is 115452024521411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114125420254511 - 222 = 114125416060207 is a prime.
It is a super-2 number, since 2×1141254202545112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114125420254561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57062710127255 + 57062710127256.
It is an arithmetic number, because the mean of its divisors is an integer number (57062710127256).
Almost surely, 2114125420254511 is an apocalyptic number.
114125420254511 is a deficient number, since it is larger than the sum of its proper divisors (1).
114125420254511 is an equidigital number, since it uses as much as digits as its factorization.
114125420254511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64000, while the sum is 38.
Adding to 114125420254511 its reverse (115452024521411), we get a palindrome (229577444775922).
The spelling of 114125420254511 in words is "one hundred fourteen trillion, one hundred twenty-five billion, four hundred twenty million, two hundred fifty-four thousand, five hundred eleven".
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