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11412546610053 = 33804182203351
BaseRepresentation
bin1010011000010011000011…
…0010010110001110000101
31111102000202222212212200110
42212010300302112032011
52443440343413010203
640134503533103233
72255346354413361
oct246046062261605
944360688785613
1011412546610053
113700041045126
1213439b2927b19
1364a27721b3c4
142b6527ba22a1
1514bcee7e6d03
hexa6130c96385

11412546610053 has 4 divisors (see below), whose sum is σ = 15216728813408. Its totient is φ = 7608364406700.

The previous prime is 11412546609991. The next prime is 11412546610079. The reversal of 11412546610053 is 35001664521411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11412546610053 - 232 = 11408251642757 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11412546609993 and 11412546610020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11412546650053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902091101673 + ... + 1902091101678.

It is an arithmetic number, because the mean of its divisors is an integer number (3804182203352).

Almost surely, 211412546610053 is an apocalyptic number.

It is an amenable number.

11412546610053 is a deficient number, since it is larger than the sum of its proper divisors (3804182203355).

11412546610053 is an equidigital number, since it uses as much as digits as its factorization.

11412546610053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3804182203354.

The product of its (nonzero) digits is 86400, while the sum is 39.

The spelling of 11412546610053 in words is "eleven trillion, four hundred twelve billion, five hundred forty-six million, six hundred ten thousand, fifty-three".

Divisors: 1 3 3804182203351 11412546610053