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1141300313134 = 2570650156567
BaseRepresentation
bin10000100110111010110…
…011001011110000101110
311001002220011220001111221
4100212322303023300232
5122144340340010014
62232150042333554
7145312325411512
oct20467263136056
94032804801457
101141300313134
11400028300593
121652371ba2ba
1383816375197
143d34c638142
151ea4b6dab24
hex109baccbc2e

1141300313134 has 4 divisors (see below), whose sum is σ = 1711950469704. Its totient is φ = 570650156566.

The previous prime is 1141300313117. The next prime is 1141300313173. The reversal of 1141300313134 is 4313130031411.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1141300313099 and 1141300313108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285325078282 + ... + 285325078285.

It is an arithmetic number, because the mean of its divisors is an integer number (427987617426).

Almost surely, 21141300313134 is an apocalyptic number.

1141300313134 is a deficient number, since it is larger than the sum of its proper divisors (570650156570).

1141300313134 is an equidigital number, since it uses as much as digits as its factorization.

1141300313134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 570650156569.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1141300313134 its reverse (4313130031411), we get a palindrome (5454430344545).

The spelling of 1141300313134 in words is "one trillion, one hundred forty-one billion, three hundred million, three hundred thirteen thousand, one hundred thirty-four".

Divisors: 1 2 570650156567 1141300313134