1141300403 has 4 divisors (see below), whose sum is σ = 1141395528. Its totient is φ = 1141205280.

The previous prime is 1141300399. The next prime is 1141300421. The reversal of 1141300403 is 3040031411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3040031411 = 353 ⋅8611987.

It is a cyclic number.

It is not a de Polignac number, because 1141300403 - 2² = 1141300399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141300103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26438 + ... + 54603.

It is an arithmetic number, because the mean of its divisors is an integer number (285348882).

Almost surely, 2^1141300403 is an apocalyptic number.

1141300403 is a deficient number, since it is larger than the sum of its proper divisors (95125).

1141300403 is an equidigital number, since it uses as much as digits as its factorization.

1141300403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95124.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1141300403 is about 33783.1378501169. The cubic root of 1141300403 is about 1045.0409858546.

Adding to 1141300403 its reverse (3040031411), we get a palindrome (4181331814).

The spelling of 1141300403 in words is "one billion, one hundred forty-one million, three hundred thousand, four hundred three".