Base | Representation |
---|---|
bin | 10101010000100010… |
… | …01110001100001101 |
3 | 1002110101121120011021 |
4 | 22220101032030031 |
5 | 141333213141303 |
6 | 5124300354141 |
7 | 552553040011 |
oct | 125021161415 |
9 | 32411546137 |
10 | 11413021453 |
11 | 4927397a39 |
12 | 2266245951 |
13 | 10cb677b42 |
14 | 7a3aa4541 |
15 | 46be75ebd |
hex | 2a844e30d |
11413021453 has 2 divisors, whose sum is σ = 11413021454. Its totient is φ = 11413021452.
The previous prime is 11413021397. The next prime is 11413021481. The reversal of 11413021453 is 35412031411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10717011529 + 696009924 = 103523^2 + 26382^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413021453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413024453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706510726 + 5706510727.
It is an arithmetic number, because the mean of its divisors is an integer number (5706510727).
Almost surely, 211413021453 is an apocalyptic number.
It is an amenable number.
11413021453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413021453 is an equidigital number, since it uses as much as digits as its factorization.
11413021453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11413021453 its reverse (35412031411), we get a palindrome (46825052864).
The spelling of 11413021453 in words is "eleven billion, four hundred thirteen million, twenty-one thousand, four hundred fifty-three".
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