11413123101001 has 4 divisors (see below), whose sum is σ = 11456519006592. Its totient is φ = 11369727195412.

The previous prime is 11413123100969. The next prime is 11413123101031. The reversal of 11413123101001 is 10010132131411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11413123101001 - 2⁵ = 11413123100969 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11413123101001.

It is not an unprimeable number, because it can be changed into a prime (11413123101031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21697952401 + ... + 21697952926.

It is an arithmetic number, because the mean of its divisors is an integer number (2864129751648).

Almost surely, 2^{11413123101001} is an apocalyptic number.

It is an amenable number.

11413123101001 is a deficient number, since it is larger than the sum of its proper divisors (43395905591).

11413123101001 is an equidigital number, since it uses as much as digits as its factorization.

11413123101001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43395905590.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 11413123101001 its reverse (10010132131411), we get a palindrome (21423255232412).

The spelling of 11413123101001 in words is "eleven trillion, four hundred thirteen billion, one hundred twenty-three million, one hundred one thousand, one".