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114131320003 = 176713607059
BaseRepresentation
bin110101001001011000…
…0011011110011000011
3101220121000012210000001
41222102300123303003
53332220104220003
6124233050140431
711150165133121
oct1522260336303
9356530183001
10114131320003
1144448177a68
121a152421717
13a9bb3a9b5c
145749b5c911
152e7eb5c61d
hex1a92c1bcc3

114131320003 has 4 divisors (see below), whose sum is σ = 120844927080. Its totient is φ = 107417712928.

The previous prime is 114131319977. The next prime is 114131320013. The reversal of 114131320003 is 300023131411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300023131411 = 359835719029.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114131320003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114131320013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3356803513 + ... + 3356803546.

It is an arithmetic number, because the mean of its divisors is an integer number (30211231770).

Almost surely, 2114131320003 is an apocalyptic number.

114131320003 is a deficient number, since it is larger than the sum of its proper divisors (6713607077).

114131320003 is an equidigital number, since it uses as much as digits as its factorization.

114131320003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6713607076.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 114131320003 its reverse (300023131411), we get a palindrome (414154451414).

The spelling of 114131320003 in words is "one hundred fourteen billion, one hundred thirty-one million, three hundred twenty thousand, three".

Divisors: 1 17 6713607059 114131320003