Base | Representation |
---|---|
bin | 11001111100110101101111… |
… | …010011111001010011000011 |
3 | 112222002220201122110100002011 |
4 | 121330311233103321103003 |
5 | 104424414401030134021 |
6 | 1042423310552433351 |
7 | 33016524120340423 |
oct | 3174655723712303 |
9 | 488086648410064 |
10 | 114132033443011 |
11 | 3340313a50a801 |
12 | 109736770a8857 |
13 | 4b8b7b2327c1c |
14 | 202803c82c483 |
15 | d2dc81cecde1 |
hex | 67cd6f4f94c3 |
114132033443011 has 2 divisors, whose sum is σ = 114132033443012. Its totient is φ = 114132033443010.
The previous prime is 114132033443009. The next prime is 114132033443027. The reversal of 114132033443011 is 110344330231411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114132033443011 - 21 = 114132033443009 is a prime.
It is a super-2 number, since 2×1141320334430112 (a number of 29 digits) contains 22 as substring.
Together with 114132033443009, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (114132033443111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066016721505 + 57066016721506.
It is an arithmetic number, because the mean of its divisors is an integer number (57066016721506).
Almost surely, 2114132033443011 is an apocalyptic number.
114132033443011 is a deficient number, since it is larger than the sum of its proper divisors (1).
114132033443011 is an equidigital number, since it uses as much as digits as its factorization.
114132033443011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 114132033443011 its reverse (110344330231411), we get a palindrome (224476363674422).
The spelling of 114132033443011 in words is "one hundred fourteen trillion, one hundred thirty-two billion, thirty-three million, four hundred forty-three thousand, eleven".
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