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1141321133081 is a prime number
BaseRepresentation
bin10000100110111100000…
…010100110110000011001
311001002221122001211010002
4100212330002212300121
5122144411202224311
62232152104502345
7145313000364203
oct20467402466031
94032848054102
101141321133081
11400039030958
1216524217a9b5
138381a78488c
143d3512d7773
151ea4d44e93b
hex109bc0a6c19

1141321133081 has 2 divisors, whose sum is σ = 1141321133082. Its totient is φ = 1141321133080.

The previous prime is 1141321133003. The next prime is 1141321133177. The reversal of 1141321133081 is 1803311231411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1055129568025 + 86191565056 = 1027195^2 + 293584^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1141321133081 is a prime.

It is a super-2 number, since 2×11413211330812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1141321133581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570660566540 + 570660566541.

It is an arithmetic number, because the mean of its divisors is an integer number (570660566541).

Almost surely, 21141321133081 is an apocalyptic number.

It is an amenable number.

1141321133081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141321133081 is an equidigital number, since it uses as much as digits as its factorization.

1141321133081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 29.

Adding to 1141321133081 its reverse (1803311231411), we get a palindrome (2944632364492).

The spelling of 1141321133081 in words is "one trillion, one hundred forty-one billion, three hundred twenty-one million, one hundred thirty-three thousand, eighty-one".