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11413221441 = 33804407147
BaseRepresentation
bin10101010000100011…
…11111000001000001
31002110101222201111020
422220101333001001
5141333241041231
65124304540053
7552554532036
oct125021770101
932411881436
1011413221441
114927514216
122266321629
1310cb717b8b
147a3b1738d
1546beb5396
hex2a847f041

11413221441 has 4 divisors (see below), whose sum is σ = 15217628592. Its totient is φ = 7608814292.

The previous prime is 11413221389. The next prime is 11413221461. The reversal of 11413221441 is 14412231411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11413221441 - 210 = 11413220417 is a prime.

It is a super-2 number, since 2×114132214412 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11413221461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902203571 + ... + 1902203576.

It is an arithmetic number, because the mean of its divisors is an integer number (3804407148).

Almost surely, 211413221441 is an apocalyptic number.

It is an amenable number.

11413221441 is a deficient number, since it is larger than the sum of its proper divisors (3804407151).

11413221441 is an equidigital number, since it uses as much as digits as its factorization.

11413221441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3804407150.

The product of its digits is 768, while the sum is 24.

Adding to 11413221441 its reverse (14412231411), we get a palindrome (25825452852).

The spelling of 11413221441 in words is "eleven billion, four hundred thirteen million, two hundred twenty-one thousand, four hundred forty-one".

Divisors: 1 3 3804407147 11413221441