Base | Representation |
---|---|
bin | 110101001001011010… |
… | …0001101101111110111 |
3 | 101220121002002010102210 |
4 | 1222102310031233313 |
5 | 3332220332423111 |
6 | 124233123304503 |
7 | 11150206431324 |
oct | 1522264155767 |
9 | 356532063383 |
10 | 114132311031 |
11 | 444487945a2 |
12 | 1a15281b133 |
13 | a9bb665c6b |
14 | 5749d39b4b |
15 | 2e7eca60a6 |
hex | 1a92d0dbf7 |
114132311031 has 8 divisors (see below), whose sum is σ = 152179477120. Its totient is φ = 76086676152.
The previous prime is 114132311017. The next prime is 114132311047. The reversal of 114132311031 is 130113231411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 114132311031 - 210 = 114132310007 is a prime.
It is a super-2 number, since 2×1141323110312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114132310989 and 114132311007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114132311071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195835 + ... + 516348.
It is an arithmetic number, because the mean of its divisors is an integer number (19022434640).
Almost surely, 2114132311031 is an apocalyptic number.
114132311031 is a deficient number, since it is larger than the sum of its proper divisors (38047166089).
114132311031 is an equidigital number, since it uses as much as digits as its factorization.
114132311031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 765605.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 114132311031 its reverse (130113231411), we get a palindrome (244245542442).
The spelling of 114132311031 in words is "one hundred fourteen billion, one hundred thirty-two million, three hundred eleven thousand, thirty-one".
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