Base | Representation |
---|---|
bin | 110101001001011010… |
… | …0010011001000101111 |
3 | 101220121002010020201021 |
4 | 1222102310103020233 |
5 | 3332220334124403 |
6 | 124233123555011 |
7 | 11150206552555 |
oct | 1522264231057 |
9 | 356532106637 |
10 | 114132333103 |
11 | 444487aa138 |
12 | 1a15282ba67 |
13 | a9bb673019 |
14 | 5749d43bd5 |
15 | 2e7ecac8bd |
hex | 1a92d1322f |
114132333103 has 2 divisors, whose sum is σ = 114132333104. Its totient is φ = 114132333102.
The previous prime is 114132333037. The next prime is 114132333113. The reversal of 114132333103 is 301333231411.
It is a strong prime.
It is an emirp because it is prime and its reverse (301333231411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114132333103 - 221 = 114130235951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114132333113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066166551 + 57066166552.
It is an arithmetic number, because the mean of its divisors is an integer number (57066166552).
Almost surely, 2114132333103 is an apocalyptic number.
114132333103 is a deficient number, since it is larger than the sum of its proper divisors (1).
114132333103 is an equidigital number, since it uses as much as digits as its factorization.
114132333103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 114132333103 its reverse (301333231411), we get a palindrome (415465564514).
The spelling of 114132333103 in words is "one hundred fourteen billion, one hundred thirty-two million, three hundred thirty-three thousand, one hundred three".
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