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11413343020 = 2254113918711
BaseRepresentation
bin10101010000100100…
…11100101100101100
31002110102012220021011
422220102130230230
5141333303434040
65124311315004
7552555546352
oct125022345454
932412186234
1011413343020
1149275975a2
12226637ba64
1310cb75b311
147a3b497d2
1546bedb3ea
hex2a849cb2c

11413343020 has 24 divisors (see below), whose sum is σ = 24552607968. Its totient is φ = 4453987200.

The previous prime is 11413343009. The next prime is 11413343027. The reversal of 11413343020 is 2034331411.

It is a junction number, because it is equal to n+sod(n) for n = 11413342982 and 11413343000.

It is not an unprimeable number, because it can be changed into a prime (11413343027) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6958536 + ... + 6960175.

It is an arithmetic number, because the mean of its divisors is an integer number (1023025332).

Almost surely, 211413343020 is an apocalyptic number.

11413343020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11413343020 is an abundant number, since it is smaller than the sum of its proper divisors (13139264948).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11413343020 is a wasteful number, since it uses less digits than its factorization.

11413343020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13918761 (or 13918759 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 11413343020 its reverse (2034331411), we get a palindrome (13447674431).

The spelling of 11413343020 in words is "eleven billion, four hundred thirteen million, three hundred forty-three thousand, twenty".

Divisors: 1 2 4 5 10 20 41 82 164 205 410 820 13918711 27837422 55674844 69593555 139187110 278374220 570667151 1141334302 2282668604 2853335755 5706671510 11413343020