Base | Representation |
---|---|
bin | 11001111100110111100100… |
… | …101110011101101011110111 |
3 | 112222010002210221011120120121 |
4 | 121330313210232131223313 |
5 | 104424432414323421241 |
6 | 1042424234242312411 |
7 | 33016624000243366 |
oct | 3174674456355367 |
9 | 488102727146517 |
10 | 114134003342071 |
11 | 33403a60468059 |
12 | 10973b26958707 |
13 | 4b8ba3749337b |
14 | 20281882cd7dd |
15 | d2dd49c16ad1 |
hex | 67cde4b9daf7 |
114134003342071 has 2 divisors, whose sum is σ = 114134003342072. Its totient is φ = 114134003342070.
The previous prime is 114134003342003. The next prime is 114134003342123. The reversal of 114134003342071 is 170243300431411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114134003342071 - 223 = 114133994953463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114134003322071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067001671035 + 57067001671036.
It is an arithmetic number, because the mean of its divisors is an integer number (57067001671036).
Almost surely, 2114134003342071 is an apocalyptic number.
114134003342071 is a deficient number, since it is larger than the sum of its proper divisors (1).
114134003342071 is an equidigital number, since it uses as much as digits as its factorization.
114134003342071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 114134003342071 its reverse (170243300431411), we get a palindrome (284377303773482).
The spelling of 114134003342071 in words is "one hundred fourteen trillion, one hundred thirty-four billion, three million, three hundred forty-two thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •