Search a number
-
+
1141340103433 = 2118776167839
BaseRepresentation
bin10000100110111101001…
…010111110001100001001
311001002222221202121112201
4100212331022332030021
5122144431031302213
62232154023240201
7145313320544305
oct20467512761411
94032887677481
101141340103433
11400048808632
121652485a9061
138382169743a
143d353a34d05
151ea4ee4a6dd
hex109bd2be309

1141340103433 has 8 divisors (see below), whose sum is σ = 1148057066240. Its totient is φ = 1134635478480.

The previous prime is 1141340103419. The next prime is 1141340103461. The reversal of 1141340103433 is 3343010431411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1141340103433 - 229 = 1140803232521 is a prime.

It is a super-2 number, since 2×11413401034332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141340103413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2898873 + ... + 3268966.

It is an arithmetic number, because the mean of its divisors is an integer number (143507133280).

Almost surely, 21141340103433 is an apocalyptic number.

It is an amenable number.

1141340103433 is a deficient number, since it is larger than the sum of its proper divisors (6716962807).

1141340103433 is an equidigital number, since it uses as much as digits as its factorization.

1141340103433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6168927.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1141340103433 its reverse (3343010431411), we get a palindrome (4484350534844).

The spelling of 1141340103433 in words is "one trillion, one hundred forty-one billion, three hundred forty million, one hundred three thousand, four hundred thirty-three".

Divisors: 1 211 877 185047 6167839 1301414029 5409194803 1141340103433