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1141340103461 is a prime number
BaseRepresentation
bin10000100110111101001…
…010111110001100100101
311001002222221202121120202
4100212331022332030211
5122144431031302321
62232154023240245
7145313320544345
oct20467512761445
94032887677522
101141340103461
11400048808658
121652485a9085
138382169745c
143d353a34d25
151ea4ee4a70b
hex109bd2be325

1141340103461 has 2 divisors, whose sum is σ = 1141340103462. Its totient is φ = 1141340103460.

The previous prime is 1141340103419. The next prime is 1141340103469. The reversal of 1141340103461 is 1643010431411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 932016468100 + 209323635361 = 965410^2 + 457519^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1141340103461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141340103469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570670051730 + 570670051731.

It is an arithmetic number, because the mean of its divisors is an integer number (570670051731).

Almost surely, 21141340103461 is an apocalyptic number.

It is an amenable number.

1141340103461 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141340103461 is an equidigital number, since it uses as much as digits as its factorization.

1141340103461 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 1141340103461 its reverse (1643010431411), we get a palindrome (2784350534872).

The spelling of 1141340103461 in words is "one trillion, one hundred forty-one billion, three hundred forty million, one hundred three thousand, four hundred sixty-one".