1141341313331 has 4 divisors (see below), whose sum is σ = 1141721636664. Its totient is φ = 1140960990000.

The previous prime is 1141341313283. The next prime is 1141341313367. The reversal of 1141341313331 is 1333131431411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1141341313331 is a prime.

It is a super-2 number, since 2×1141341313331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1141341313294 and 1141341313303.

It is not an unprimeable number, because it can be changed into a prime (1141341313391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190157165 + ... + 190163166.

It is an arithmetic number, because the mean of its divisors is an integer number (285430409166).

Almost surely, 2^{1141341313331} is an apocalyptic number.

1141341313331 is a deficient number, since it is larger than the sum of its proper divisors (380323333).

1141341313331 is an equidigital number, since it uses as much as digits as its factorization.

1141341313331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380323332.

The product of its digits is 3888, while the sum is 29.

Adding to 1141341313331 its reverse (1333131431411), we get a palindrome (2474472744742).

The spelling of 1141341313331 in words is "one trillion, one hundred forty-one billion, three hundred forty-one million, three hundred thirteen thousand, three hundred thirty-one".