Base | Representation |
---|---|
bin | 1010011000010110010100… |
… | …0001111001100111100001 |
3 | 1111102010001002011022012012 |
4 | 2212011211001321213201 |
5 | 2443444142303234213 |
6 | 40135130523242305 |
7 | 2255410156443632 |
oct | 246054501714741 |
9 | 44363032138165 |
10 | 11413423102433 |
11 | 37004508808a0 |
12 | 1343bb8379395 |
13 | 64a3869a3c51 |
14 | 2b65ac35d889 |
15 | 14bd5172d4a8 |
hex | a61650799e1 |
11413423102433 has 16 divisors (see below), whose sum is σ = 13007880365760. Its totient is φ = 9918862968000.
The previous prime is 11413423102409. The next prime is 11413423102441. The reversal of 11413423102433 is 33420132431411.
It is a cyclic number.
It is not a de Polignac number, because 11413423102433 - 214 = 11413423086049 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 11413423102433.
It is not an unprimeable number, because it can be changed into a prime (11413423105433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 177090335 + ... + 177154772.
It is an arithmetic number, because the mean of its divisors is an integer number (812992522860).
Almost surely, 211413423102433 is an apocalyptic number.
It is an amenable number.
11413423102433 is a deficient number, since it is larger than the sum of its proper divisors (1594457263327).
11413423102433 is a wasteful number, since it uses less digits than its factorization.
11413423102433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354245248.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 11413423102433 its reverse (33420132431411), we get a palindrome (44833555533844).
The spelling of 11413423102433 in words is "eleven trillion, four hundred thirteen billion, four hundred twenty-three million, one hundred two thousand, four hundred thirty-three".
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